# How do you find the vertex and intercepts for #y=-x^2+2x+3#?

##### 1 Answer

Mar 18, 2016

vertex (1, 4)

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex:

y(1) = -1 + 2 + 3 = 4

Vertex (1, 4)

To find y-intercept, make x = 0 --> y = 3

To find x-intercepts, make y = 0, and solve the quadratic equation

Since (a - b + c = 0), use shortcut. The 2 real roots (x -intercepts) are:

- 1 and