# How do you write #y=-x^2-2x+3# in vertex form and identify the vertex, y intercept and x intercept?

##### 1 Answer

May 19, 2015

y = -x^2 - 2x + 3

x of vertex: x = (-b/2a) = 2/-2 = -1

y of vertex: f(-1) = -1 + 2 + 3 = 4

Vertex form:

Check by developing: f(x) = -(x^2 + 2x + 1) + 4 = -x^2 - 2x + 3. OK

x-intercepts: y = 0.

Since a + b + c = 0, one real root is